Tlong, besok di kumpul ni,

Mapel Math
Bab Juring

Penyelesaian :
a). Luas juring AOB
= 75/360 × phi × r^2
= 5/24 × 22/7 × 21 cm × 21 cm
= 5/24 × 1386 cm
= 288,75 cm^2

b). Keliling juring AOB
= 75/360 × 2 × phi × r
= 5/24 × 2 × 22/7 × 21
= 5/24 × 132 cm
= 27,5 cm

Semoga Membantu

a.) Luas juring AOB

[tex]L = \frac{75}{360} \times \pi {r}^{2} \\ \\ L = \frac{5}{24} \times \frac{22}{7} \times 21 \times 21 \\ \\ L = {288,75~cm}^{2} [/tex]

b.) Keliling AOB

[tex]K = \frac{75}{360} \times 2\pi{r} \\ \\ K = \frac{5}{24} \times 2 \times \frac{22}{7} \times 21 \\ \\ K = 27,5~cm[/tex]