Diberikan persamaan x-2/3 + y+1/6=2 dan x+3/ - 2y-1/=1, Maka nilai 1/x+y=..... Help Me Please???

[tex] \frac{x - 2}{3 + y} + \frac{1}{6} = 2 \\ \frac{x - 2}{3 + y} = \frac{11}{6} \\ 6(x - 2) = 11(3 + y) \\ 6x = 3y + 45 \\ 2x - y - 15 = 0[/tex]
[tex] \frac{x + 3}{ - 2y - 1} = 1 \\ x = - 2y - 4 \\ x + 2y + 4 = 0[/tex]
eliminasikan
[tex]4x - 2y - 30 = 0 \\ x + 2y + 4 = 0 + \\ 5x = 26 \\ x = \frac{26}{5} [/tex]
subtitusikan
[tex] \frac{26}{5} + 2y + 4 = 0 \\ 2y + \frac{46}{5} = 0 \\ y = - \frac{23}{5} [/tex]

[tex] \frac{1}{x + y} = \frac{1}{ \frac{26}{5} - \frac{23}{5} } = \frac{5}{3} [/tex]