Diketahui a= 2log3 dan b=2log5. Nilai 2log135 adlah?

²log3 = a
²log5 = b
²log 135 = ²log(3³ x 5)
= ²log 3³ + ²log5
= 3. ²log3 + b
= 3a + b

²log3=a
²log5=b

²log 135
=²log (5x27)
=²log 5 + ²log 27
=b + 3.²log 3
=b+3a

semoga membantu........