Diketahui 2log 7 = a dan 2log 3 = b. Tentukan nilai dari 6log 14

2log7 = a ; 2log3 = b
6 log 14
= {2 log 14} : {2 log 6}
= {2 log (2 x 7) } : {2 log (2 x 3) }
= {2 log 2 + 2 log 7} : {2 log 2 + 2 log 3}
= {1 + a} : {1 + b}
= (a + 1) / (b + 1)

Mapel : Matematika
Bab: Logaritma

^2log7 = a
^2log3 = b

^6log14

= ^2 log 14/^2log 6

= ^2 log ( 7 × 2 )/ ^2 log (3 × 2)

= ^2log 7 + ^2log2 / ^2log3 + ^2 log 2

(^2 log 2 = 1 karena ^aloga = 1)

= a + 1/b + 1