Matematika

Pertanyaan

jika Cot alpha=4/3,hitunglah nilai dari (1+sin alpha).(1-sin alpha)/(1+cos alpha).(1-cos alpha)

1 Jawaban

  • cot a = 4/3
    cot a = x/y
    r = V(4^2 + 3^)
    r = V(16+9)
    r = V25
    r = 5
    cos a = 4/5
    (1+sin a)(1-sin.a)/(1+cos a)(1-cos a)
    = (1 - sin^2 a ) / (1 - cos^2 a)
    = cos^2 a / (1 - cos^2 a)
    = (4/5)^2 / (1 - 4/5^2)
    = 16/25 / (1- 16/25)
    = (16/25) / (9/25)
    = 16/9
    = 1 7/9

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