f(×)= ax + b f(2)= 7 dan f(3)= 12. Nilai f(3) =…………

f(2)=> 2a + b =7
f(3)=> 3a + b =12
--------------- -
-a= -5
a= 5

2a + b = 7
2.5 + b = 7
10 + b = 7
b = 7-10
b = -3

=> f(x) = ax + b
f(3) = 3a + b
= 3.5 + (-3)
= 15 - 3
= 12

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