boleh tolong yg nomor 40
Kimia
mnathaniaherrit
Pertanyaan
boleh tolong yg nomor 40
1 Jawaban
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1. Jawaban Ricoam216
a.
Anode = [tex]PbO_{2} + 2 H^{+} + 2e + H_{2}S O_{4}[/tex] -> [tex]PbSO_{4} + 2 H_{2}O [/tex]
Katode = [tex]Pb + S O_{4} [/tex] -> [tex]PbSO_{4} [/tex]
b. terurai menjadi elektolit
c.
Anode = [tex]PbSO_{4}+SO_{4}^{ 2-} + 2 H_{2}O [/tex] -> [tex]PbO_{2} + 2H_{2} S O_{4} [/tex]
Katode = [tex] PbSO_{4} + 2 H^{+} [/tex] -> [tex] Pb + H_{2}S O_{4} [/tex]