F(x)=x+2,g(x)=4^x dan h(x)=2logx,x>0.Tentukan fungsi komposisi a) (fogoh)^-1(x)dan(fogoh)^-1(4)

(goh) (x) = g(h(x))
= g(2log x)
= 4^(2log x)
= 2^2^(2log x)
= 2^(2logx^2)
= x^2
(fogoh) (x) = f((goh)(x))
= x^2 + 2
Sekarang lagi di invers , buat seolah olah (fogoh) (x) = y didapat
y = x^2 + 2
y - 2 = x^2
√(y - 2) = x
Jadi (fogoh)^-1(x) = √(x - 2)
(fogoh)^-1(4) = √(4-2)
(fogoh)^-1(4) = √2