\frac{2 \sqrt{3}-1 }{ \sqrt{3}+2 } ?

[tex]\displaystyle \frac{2\sqrt{3}-1}{\sqrt{3}+2} = \frac{2\sqrt{3}-1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}} \\ \\ \frac{4\sqrt{3}-6-2+\sqrt{3}}{1}=5\sqrt{3}-8[/tex]