diketahui f(x)=3x-1 dan (gof)(x)=9x^2-6x+4 maka (fog)(x)= beserta cara dan penjelasan

[tex]f(x)=3x-1 \\ (g\circ f)(x)=9x^2-6x+4 \\ g(f(x))=9x^2-6x+4 \\ g(3x-1)=9x^2-6x+4 \\ g(3x) = 9(x+1)^2-6(x+1)+4 \\ g(x)=9(\frac{x+1}{3})^2-6(\frac{x+1}{3})+4 \\ g(x)=(x+1)^2-2(x+1)+4 \\ g(x)=x^2+2x+1-2x-2+4 \\ g(x)=x^2+3 \\ \\ $Maka,$ \\ (f\circ g)(x)=f(g(x)) \\ (f\circ g)(x)=f(x^2+3) \\ (f\circ g)(x)=3(x^2+3)-1 \\ (f\circ g)(x)=3x^2+9-1 \\ (f\circ g)(x)=3x^2+8[/tex]