Matematika

Pertanyaan

tlong bntu jwab kk,
yg tw pleasee..
tlong bntu jwab kk, yg tw pleasee..

1 Jawaban

  • P(1,0) ~ (x1,0)
    Q(2,0) ~ (x2,0)
    (0,6) ~ (x,y)

    Y = a(x-x1) (x-x2)
    6 = a (0-1) (0-2)
    6 = 2a
    3 = a

    Y = a (x-x1) (x-x2)
    Y = 3 ( x^2 -3x + 2)
    Y = 3x^2 -9x + 6