(√3+½)²+(½√3x1)² beserta penyesaiannya ya Kak. Secpatnya ya Kak d selesaikan

[tex] { \sqrt{3} }^{2} = \sqrt{3} \times \sqrt{3} \\ \: \: \: \: \: \: \: \: \: = \sqrt{9} \\ \: \: \: \: \: \: \: \: \: = 3 \\ \\ { \frac{1}{2} }^{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \\ \\ { { \frac{1}{2} }^{2} \times \sqrt{3} }^{2} = \frac{1}{4} \times 3 = \frac{3}{4} [/tex]
maka caranya:
[tex] = {( \sqrt{3} + \frac{1}{2}) }^{2} + {( \frac{1}{2} \sqrt{3} \times 1) }^{2} \\ = ( { \sqrt{3} }^{2} + { \frac{1}{2} }^{2} ) + ( {( \frac{1}{2} \sqrt{3} )}^{2} \times {1}^{2} ) \\ = ( \frac{3}{1} + \frac{1}{4} ) + ( \frac{3}{4} \times \frac{1}{1} ) \\ = ( \frac{3 \times 4}{1 \times 4} + \frac{1}{4} ) + \frac{3}{4} \\ = ( \frac{12}{4} + \frac{1}{4} ) + \frac{3}{4} \\ = \frac{13}{4} + \frac{3}{4} \\ = \frac{16}{4} \\ = 4[/tex]