Matematika

Pertanyaan

tentukan HP!
y-x=2
2x^2+5y-5xy=8

1 Jawaban

  • y-x = 2
    y = x + 2
    [tex]2x^2+5y(1-x)=8 \\ 2x^2+5(x+2)(1-x)=8 \\ 2x^2+5x-5x^2+10-10x=8 \\ -3x^2-5x+2=0 \\ 3x^2+5x-2=0 \\ (x+2)(3x-1)=0 \\ x_1=-2 \\ x_2=\frac{1}{3} \\ \\ y_1=x_1+2=-2+2=0 \\ y_2=\frac{1}{3}+2=\frac{7}{3} \\ \\ HP=\{(x,y)|(-2,0),(\frac{1}{3},\frac{7}{3})\}[/tex]

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