tolong bantu ya..... Terimakasih

8+3-2=11-2=9:3=3 itu jawabannya

[tex] \frac{x - 1}{ \sqrt{ {x}^{2} + 3 } - 2} . \frac{ \sqrt{ {x}^{2} + 3 } + 2 }{ \sqrt{ {x}^{2} + 3} + 2 } \\ = \frac{(x - 1)( \sqrt{ {x}^{2} + 3 } + 2)}{ {x}^{2} + 3 - 4 } \\ = \frac{(x - 1)( \sqrt{ {x}^{2} + 3} + 2)}{ {x }^{2} - 1} \\ = \frac{(x - 1)( \sqrt{ {x}^{2} + 3} + 2 }{(x - 1)(x + 1)} [/tex]
(x - 1 ) coret dg ( x - 1 )
maka sisanya
[tex] = \frac{ \sqrt{ {x}^{2} + 3 } + 2 }{(x + 1)} \\ [/tex]
masukkan nilai limit mendekati 1
[tex] = \frac{ \sqrt{ {1}^{2} + 3} + 2 }{1 + 1} \\ = \frac{ \sqrt{4} + 2 }{2} \\ = \frac{2 + 2}{2} \\ = \frac{4}{2} = 2[/tex]