cara no 4 kak gimana

Fisika Kelas 7, Materi Kalor

Dik : m = 5 kg ; c = 390 J/kg°C
ΔT = 45°C - 25°C = 20°C
Dit : Q = ...?
Jawab :
Q = m.c.ΔT
Q = 5 kg × 390 J/kg°C × 20°C
Q = 39000 J
Q = 39000 / 1000 = 39 kJ (opsi D)

Q=m.c.∆t
=5.390.(45-25)
=5.390.20
=39000 joule
=39 kilo joule

jadi yang d ya...
klok kata guru ku biar mudah hafal hafalin qi(Q)ma(m)c.∆t(et)
qimacet