\frac{ \sqrt{6}- \sqrt{10}- \sqrt{12} }{ \sqrt{18} }
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Pertanyaan
\frac{ \sqrt{6}- \sqrt{10}- \sqrt{12} }{ \sqrt{18} }
1 Jawaban
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1. Jawaban Takamori37
[tex]\displaystyle \frac{ \sqrt{6}- \sqrt{10}- \sqrt{12}}{\sqrt{18}}=\frac{\sqrt{2}}{\sqrt{2}}\times \frac{\sqrt{3}-\sqrt{5}-\sqrt{6}}{\sqrt{9}} \\ \\ \frac{1}{3}(\sqrt{3}-\sqrt{5}-\sqrt{6})[/tex]