tolong jawab yaa.. pakai caranya terimakasih

Kelas 11 Matematika
Bab Limit

lim ((x² - x - 6)/(4 - √(5x + 1)) 
x→3

= lim ((x - 3) (x + 2)/(4 - √(5x + 1)) . ((4 + √(5x + 1)/(4 + √(5x + 1))
   x→3

= lim ((x - 3) (x + 2) (4 + √(5x + 1)) / (16 - (5x + 1))
   x→3

= lim ((x - 3) (x + 2) (4 + √(5x + 1)) / (15 - 5x))
   x→3

= lim (- (3 - x) (x + 2) (4 + √(5x + 1)) / (5 (3 - x))
   x→3

= - (3 + 2) . (4 + √(5 . 3 + 1)) / 5
= - (4 + √16)
= - (4 + 4)
= -8