Tolong caranya y kakak, dpt tinggi

[tex] \tan(45) = \frac{y}{80 - a} = 1 \\ y = 80 - a \\ \tan(60) = \frac{y}{a} = \sqrt{3} \\ y = a \sqrt{3} \\ 80 - a = a \sqrt{3} \\ 80 = a(1 + \sqrt{3} ) \\a = \frac{80}{1 + \sqrt{3} } \\ y = \frac{80 \sqrt{3} }{1 + \sqrt{3} } = \frac{80 \sqrt{3}(1 - \sqrt{3}) }{ - 2} = - 40 \sqrt{3} (1 - \sqrt{3} ) \\ = 120 - 40 \sqrt{3} \\ maka \: tinggi \: balon \: dari \: tanah \: = 150 + 120 - 40 \sqrt{3} \\ = 270 - 40 \sqrt{3} [/tex]