6+3+3/2+3/4+3/8+.... berapa geometri tak terhingga?
Matematika
TriKurnia11
Pertanyaan
6+3+3/2+3/4+3/8+.... berapa geometri tak terhingga?
1 Jawaban
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1. Jawaban CvanLF
a = 6
r = [tex] \frac{3}{6} [/tex] = [tex] \frac{1}{2} [/tex]
Sn = [tex] \frac{a}{1 - r} [/tex]
Sn = [tex] \frac{6}{1 - \frac{1}2} } [/tex]
Sn = [tex] \frac{6}{ \frac{1}{1} \frac{1}{2} } [/tex]
Sn = 6 · [tex] \frac{1}{2} [/tex]
Sn = 12