3(13-y)=8y-(5y-7) tolong dijawab cepat ya, besok dikumpul!!!!!!!

= 39 - 3 y = 8y - 5y + 7
= 39 - 3y = 3y + 7
= -3y - 3y = 7 - 39
= -6y = -32
[tex]y = \frac{16}{3} [/tex]

3(13-y)=8y-(5y-7)
39-3y=8y(-5y+7)
39-3y=-40y^2+56y
-56y-3y=-40y^2-39
-59y=-40y^2-39
-59=-40y-39
40y=59-39
40y=20
y=20/40=1/2