hitunglah: A. [tex](7 \sqrt{7} )^{ \frac{2}{3} } [/tex] B. [tex]( \frac{1}{2} \sqrt{2} )^{ - 4} [/tex]

A.
[tex] = {(7 \sqrt{7} )}^{ \frac{2}{3} } \\ = \sqrt[3]{ {(7 \sqrt{7})}^{2} } \\ = \sqrt[3]{49 \times 7} \\ = \sqrt[3]{343} \\ = 7[/tex]
B.
[tex] = {( \frac{1}{2} \sqrt{2}) }^{ - 4} \\ = {( \frac{1}{ \sqrt{2} } )}^{ - 4} \\ = { \sqrt{2} }^{4} \\ = {2}^{2} \\ = 4[/tex]