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mohon bantuannya gays:v
mohon bantuannya gays:v

1 Jawaban

  • Np= 1200
    Ns= 400
    Vp= 300v
    Ps= 100 watt

    ditanya Ip?

    •cari Vs dulu
    Np/Ns=Vp/Vs
    1200/400=300/Vs
    3/1=300/Vs
    3Vs= 300
    Vs= 100

    •daya di sekunder
    Ps=Vs.Is
    100= 100.Is
    1 A=Is

    •cari Ip
    Np/Ns=Is/Ip
    1200/400=1/Ip
    3/1=1/Ip
    3Ip=1
    Ip= 1/3 A

    jadi Ip= 1/3A

    semoga membantuu :)