mohon bantuannya gays:v
Fisika
adit1620
Pertanyaan
mohon bantuannya gays:v
1 Jawaban
-
1. Jawaban Luhgedeayuu
Np= 1200
Ns= 400
Vp= 300v
Ps= 100 watt
ditanya Ip?
•cari Vs dulu
Np/Ns=Vp/Vs
1200/400=300/Vs
3/1=300/Vs
3Vs= 300
Vs= 100
•daya di sekunder
Ps=Vs.Is
100= 100.Is
1 A=Is
•cari Ip
Np/Ns=Is/Ip
1200/400=1/Ip
3/1=1/Ip
3Ip=1
Ip= 1/3 A
jadi Ip= 1/3A
semoga membantuu :)