tlong bntu jwab kk.. yg tw please..

analisis gambar parabola :
- titik potong sumbu y (0,1)
- titik puncak maksimum (2,4)
xp= 2
yp= 4
- parabola terbuka kebawah (a < 0 )
- maka fungsi kuadrat :
[tex]y = a {(x - xp)}^{2} + yp \\ 1 = a {(0 - 2)}^{2} + 4 \\ 1 = 4a + 4 \\ 4a = - 3 \\ a = - \frac{3}{4} \\ y = - \frac{3}{4} {(x - 2)}^{2} + 4 \\ y = - \frac{3}{4} ( {x}^{2} - 4x + 4) + 4 \\ y = - \frac{3}{4} {x}^{2} + 3x + 1[/tex]