no 11 dan 12 gimana ya

12. sudutAOC = 2xsudutABC= 100
ADC = 180-100 = 80
11.
[tex] {ot }^{2} = {10}^{2} - {8}^{2} \\ ot = 6[/tex]
AT= 10+6=16
[tex][apq] = \frac{1}{2} \times 16 \times 16 = 128[/tex]
AQ=
[tex] \sqrt{ {8}^{2} + {16}^{2} } = \sqrt{320} = 8 \sqrt{5} [/tex]
t=
[tex] \sqrt{ {10}^{2} - {(4 \sqrt{5} )}^{2} } = \sqrt{100 - 80} = 2 \sqrt{5} [/tex]


[AOQ]= ½xAQxt
[tex] \frac{1}{2} \times 2\sqrt{5} \times 8 \sqrt{5} = \sqrt{5} \times 8 \sqrt{5} = 40[/tex]
OQT = 90-55 =35
AOQ = 180-55 = 125
APQ = ½125 = 62.5