Matematika

Pertanyaan

Nomer 12 sama 13 gimana ya caranya?
Mohon bantuan nya>
Nomer 12 sama 13 gimana ya caranya? Mohon bantuan nya>

2 Jawaban

  • 12]
    [tex] \frac{3}{4} (y + 1) - \frac{y}{5} = 9 \\ \\ 15(y + 1) - 4y = 180 \\ 15y + 15 - 4y = 180 \\ 11y = 180 - 15 \\ 11y = 165 \\ y = \frac{165}{11} \\ y = 15[/tex]

    y - 2 = 15 - 2 = 13 (Jawaban C)

    13]
    [tex]12 - 2x \geqslant 3(x - 1) \\ 12 - 2x \geqslant 3x - 3 \\ - 2x - 3x \geqslant - 3 - 12 \\ - 5x \geqslant - 15 \\ x \leqslant \frac{ - 15}{ - 5} \\ x \leqslant 3[/tex]

    HP = {x | x ≤ 3, x E Asli}

    HP {1, 2, 3}

    Jawaban A ✔
  • 12.
    3/4(y + 1) - y/5 = 9
    3/4 y + 3/4 - y/5 = 9
    20(3/4 y + 3/4 - y/5) = 20(9)
    60/4 y + 60/4 - 20y/5 = 180
    15y + 15 - 4y = 180
    15y - 4y = 180 - 15
    11y = 165
    y = 165 / 11
    y = 15

    (y - 2)
    = (15 - 2)
    = 13

    Jawabannya:
    C. 13

    13.
    12 - 2x ≥ 3(x - 1)
    12 - 2x ≥ 3x - 3
    - 3x - 2x ≥ - 12 - 3
    - 5x ≥ - 15
    5x ≤ 15
    x ≤ 15 /5
    x ≤ 3

    x ∈ bilangan Asli
    Jadi,
    Hp = {1, 2, 3,}

    Jawabannya:
    A. {1, 2, 3}

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