Nomer 12 sama 13 gimana ya caranya? Mohon bantuan nya>
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Pertanyaan
Nomer 12 sama 13 gimana ya caranya?
Mohon bantuan nya>
Mohon bantuan nya>
2 Jawaban
-
1. Jawaban AlfandyGulo
12]
[tex] \frac{3}{4} (y + 1) - \frac{y}{5} = 9 \\ \\ 15(y + 1) - 4y = 180 \\ 15y + 15 - 4y = 180 \\ 11y = 180 - 15 \\ 11y = 165 \\ y = \frac{165}{11} \\ y = 15[/tex]
y - 2 = 15 - 2 = 13 (Jawaban C)
13]
[tex]12 - 2x \geqslant 3(x - 1) \\ 12 - 2x \geqslant 3x - 3 \\ - 2x - 3x \geqslant - 3 - 12 \\ - 5x \geqslant - 15 \\ x \leqslant \frac{ - 15}{ - 5} \\ x \leqslant 3[/tex]
HP = {x | x ≤ 3, x E Asli}
HP {1, 2, 3}
Jawaban A ✔ -
2. Jawaban ArifAfkar
12.
3/4(y + 1) - y/5 = 9
3/4 y + 3/4 - y/5 = 9
20(3/4 y + 3/4 - y/5) = 20(9)
60/4 y + 60/4 - 20y/5 = 180
15y + 15 - 4y = 180
15y - 4y = 180 - 15
11y = 165
y = 165 / 11
y = 15
(y - 2)
= (15 - 2)
= 13
Jawabannya:
C. 13
13.
12 - 2x ≥ 3(x - 1)
12 - 2x ≥ 3x - 3
- 3x - 2x ≥ - 12 - 3
- 5x ≥ - 15
5x ≤ 15
x ≤ 15 /5
x ≤ 3
x ∈ bilangan Asli
Jadi,
Hp = {1, 2, 3,}
Jawabannya:
A. {1, 2, 3}
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