Soal matematika Tolong dijawab yaa.

Mapel : Matematika
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[tex] = \frac{6(3 + \sqrt{2})(3 - \sqrt{2} ) }{2 + \sqrt{7} } \times \frac{2 - \sqrt{7} }{2 - \sqrt{7} } \\ \\ = \frac{6(9 - 2)}{2 + \sqrt{7} } \times \frac{2 - \sqrt{7} }{2 - \sqrt{7} } \\ \\ = \frac{42(2 - \sqrt{7}) }{4 - 7} \\ \\ = \frac{42(2 - \sqrt{7} )}{ - 3} \\ \\ = - 14( 2 - \sqrt{7} ) \\ \\ = 14 \sqrt{7} - 14 (2) \\ \\ = 14( \sqrt{7} - 2 )[/tex]

= 14√7 - 28